191652. lajstromszámú szabadalom • Eljárás észterezett láncot hordozó difenil-azometin-származékok, valamint ezeket a vegyületeket tartalmazó gyógyszerkészítmények előállítására
191 652 Táblázat (folytatás) Vegyület X, X2 x3 R R' n Op. (°C) vagy nD (törésmutató) 17. 5-Cl 4—Cl H-ch3-c2h5 4 Op.= 73-74 18. 5-Cl 4—Cl H-ch3-ch3 1 Op.= 133-134 19. 5-Cl 4-C1 H-ch3 n—C3H7 3 Op. = 54-56 20. 5-Cl 4—Cl H-ch3-ch2-ch=ch2 3 Op.= 57-58 21. 5-Cl 4-C1 H-ch3-ch3 4 Op.= 61-62 22. 5-CH3 4—Cl H-CH3-c2h5 3 Op.= 52-53 23. 5—Cl 4—Cl H-CH3-ch3 5 Op.= 39-40 24. 5-Cl 4—Cl H-ch3-c2h5 2 Op.= 55-56 25. 5-Cl 4—Cl H-ch3 b képlet 3 Op.= 53-54 26. 5-Cl 4—Cl H n—C3H7-ch3 2 Op.= 59-70 27. 5-Cl 4-C1 H n—C3H7 —c2h5 2 Op.= 71-72 28. 5-Cl 4—Cl H-CHj n—C5Hji 3 ng1** 1,5669 29. 5—Cl 4—Cl H-ch3 —C2Hs 5 Op.= 34-35 30. 5—Cl 4-CH3 H (CH3)2-CH-CH2--C2Hs 3 ng = 1,5609 31. 5-Cl 4-C2H5 H-c2hs —c2h5 3 ng = 1,5669 32. 5-Cl 4—Cl H-ch3-ch2ch2oh 3 Op.= 74-75 33. 5—Cl 4—Cl H-ch3-ch2ch2o-ch2ch3 3 Op. = 35—36 34. 5—Cl 4—Cl H-ch3-ch2ch2o-cii3 3 Op.= 34-35 35. 5—Cl 4—Cl H-ch3 -ch2ch2o-c4h9 3 ng*« 1,5643 36. 5—Cl 4-CHj H-ch3-c2hs 3 Op.= 57-58 37. 5-Cl 4—Cl H-ch3-ch2-coo-c2h5 3 ng = 1,5700 38. 5-Cl 4—Cl H-ch3 c képlet 3 ' Op. = 77-78 39. 5-Cl 4—Cl H-ch3 —f(CH2)2—0]2CH3 3 Op.= 30-31 40. 5-Cl 4—Cl H-ch3 d képlet 3 Op.= 76-77 41. 5—Cl 4-CH3 2--ch3-ch3-c2h5 3 ng*5 = 1,5743 42. 5—Cl 4—Cl H-CHj e képlet 3 ng = 1,5575 43. 5-Cl 4-C1 H-ch3 f képlet 3 Op.= 95-96 44. 5-Cl 4-CH3 H n-C3H7-ch3 3 ng-s = 1,5774 45. 5-Cl 4—Cl H n—C3H7-ch3 4 Op.= 64—65 46. 5—Cl 4—Cl H n—C3H7 —c2h5 4 Op.= 41-42 47. 5-Cl 4—Cl H n—C3H7-ch3 5 Op.= 40-41 48. 5-CH3 4-CH3 2--ch3-ch3-ch3 3 ng = 1,5710 49. 5-Cl 4-Cl H TI—C3H7-c2hs 5 n2D3 = 1,5663 50. 5 -Cl 4—Cl H-ch3 g képlet 3 Op.= 101-102 51. 5—Cl 4-CH3 2--ch3-ch3-ch3 3 ng3 = 1,5770 52. 5—Cl 4-C1 H-ch3 h képlet 3 Op.= 102-103 53. 5—Cl 4—Cl H-ch3-CH2ChCH 3 Op.= 70-71 54. 5-CH3 4-«-C3H7 H —C2Hs-ch3 3 ng = 1,5610 55. 5-Cl 4—Cl H-ch3 i—C3H7 3 ng = 1,5751 56. 5-CH3 4—Cl 2--ch3-ch3-ch3 3 n2D2-5= 1,5810 57. 5—Cl 4—Cl H-ch3 i képlet 3 rip = 1,5725 58. 5-Cl 4-Cl H-ch3-(CH2CH20)3-CH3 3 n“ = 1,5559 59. 5-Cl 4—Cl H-ch3 j képlet 3 Op.= 58-59 60. 5-Cl 4—Cl H-ch3-ch3 7 Op.= 39-40 61. 5-Cl 4—Cl H-ch3-ch3 6 Op. = 38-39 62. 5-Cl 4—Cl H-ch3 k képlet 3 ng = 1,5751 63. 5—Cl 4—Cl H-ch3 Í-C4H9 3 Op.= 84-85 64. 5-Cl 4—Cl H-ch3-ch3 8 Op.= 37-38 65. 5-Cl 4—Cl H-ch3-CH3 9 ' Op.= 54-55 66. 5-Cl 4—Cl H n—C3H7-CH2CH20-C2H5 3 nD = C5663 67. 5-Cl 4—Cl H-ch3 —ch3 10 Op.= 39-40 68. 5 Cl 4—Cl H n—C3H7-(CH2)2-OCHj 4 n** = 1.5654 69. 5-Cl 4—Cl H n—C3H7-(CH2)20-C2Hs 4 np’s = 1,5620 70. 5-Cl 4-C1 H n—C3H-7-ch2-ch=ch2 4 Op.= 35-36 4
