156154. lajstromszámú szabadalom • Eljárás pirimidin-származékok előállítására

156154 5 6 Vegyület száma NR:1

R: 2 R3 R4 XR5 > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU 19 X > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O—S02

—CH

3 > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU 20 -K > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O—S02

-.CH

3 > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU 21 -< > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O—S02

—C

2

H

5 22 -N(CH3

)

2 > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O^CO—C6

H

5 23 -< > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O—S02

—C

e

H

4

—CH, (p) > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU 24 -N

\ > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O—S02

^C

6

H

5 25 -N(CH3

)

2 > > > > > CH3 Ph CH3 CH3 CH3 CH3 CH3 H H H C2

H

5 H H szék C5HU O—CO—C6H

5 26 -N(CH3

)

2 CH3 nC3

H

7 O—CO—CH=CH—CH3 27 —N(CH3

)

2 CH3 nC3

H

7 O—CO—CH=CH—C6H

5 28 —NH—C2

H 5 / CH3 CH3 H nü4

H

9 H H O—CO—C6H

5 29 -< 5 / CH3 CH3 H nü4

H

9 H H O—CO—C6H

5 30 —N(CHa)2 5 / CH3 CH3 H nü4

H

9 H H O—S02

—CH

3 31 -N(CH3

)

2 / CH3 CH3 Br H O^CO—CC

H

5 32 -NH-/ >-C1 CH3 CH3 Br H O—CO—C6H

3 33 -N(CH3

)

2 CH3 11C4H9 S—CO—C6H

5 34 —N(CH3

)

2 CH3 GH3 O—^CO—OC2

H

5 35 —N(CH3

)

2 CH3 CH3 O—CO—OnC4H

9 36 -N(CH3

)

2 CH3 CH3 S—CO—OnC3H

7 37 • -N(OH3

)

2 CH3 nC3

H

7 S— CO—OnC3H

7 38 —N(CH3

)

2 CH3 IÜC4H9 O—CO—OC2H5 39 —N(CH3

)

2 CH3 11G4H9 O—CO—OnC3H

7 40 —N(CH3

)

2 CH3 nXI^Hg O—CO—O11C4H9 41 -N(CH3

)

2 > CH;; nC3

H

7 nC3

H

7 11C4II9 H C2H5 S—CO—OnC3H

7 42 ~< > CH;; nC3

H

7 nC3

H

7 11C4II9 H C2H5 O—CO—C6H

5 43 -N(CH3

)

2 > CH;; nC3

H

7 nC3

H

7 11C4II9 H C2H5 O—CO—C6H

5 CHo 44 -< C2

H

5 CH3 11C4H9 O—CO—C6H

5 45 —NH2 —N(CH3

)

2 -N<CH3

)

2 Ph CH3 CH3 H O—CO—C2H5 46 —NH2 —N(CH3

)

2 -N<CH3

)

2 Ph CH3 CH3 \ /—tü2 O—CO—C6H

5 —NH2 —N(CH3

)

2 -N<CH3

)

2 Ph CH3 CH3 H 47 —NH2 —N(CH3

)

2 -N<CH3

)

2 Ph CH3 CH3 H 0—so2

—N/ ^> 48 -N(CH3

)

2 H N02 O—CO^C6

H

5