Az Eszterházy Károly Tanárképző Főiskola Tudományos Közleményei. 1990. Sectio Physicae (Acta Academiae Paedagogicae Agriensis : Nova series ; Tom. 20)

Franczia Tamás: An arialytical inethod for calculating multicentre intégrais built up from GTF—S II.

- 5 intCO CD> |^intC-oo 5x5 4-aOf ^ t p

J Cx, p}J C4da> then intC-oo +oo)f , Cx, p:>=§ántCO 5 k 5 co) 4Ck3cosCpk) C44b> g C p D ' r 71 ' If calculating 'iCk3 and that of its inverse are simpler than the direct evaluation of intC— oo 5x5 +oo3f , (x.p) it is useful to g C p 3 ' r apply to the calculation of intC—

cd 5x5 -t-oo^f , Cx,p3: flip! '

r J o + oo = f -OD f f _ ,Cx.p)dx J gCp) ' r -t-ao casCkp)dp — J" -CD S f

9Cp

JCx,p)cosCkp>dp dx = if 0tp5 Cx,p}cosCkp}dp -co + oo dx = J -oo h R

e s r c

x,

p>e

i

kPd

P -CD dx C453 It is to be seen that the first task is to evaluate + CD J f Cx,p3e

l

kPdp . Taking into account the C41>, C42a>, C42b}, -CD C43D, C44a), C44b3, C4S), C4Ó3 equations, the remark concerning the first task in calculating the right side of C4S3 moreover taking into account also the continuity and the integrability of intC-CD 5x5 +OO)f ^ c ^ Cx, p) with respect to p from 0 to +<x> and the continuity and integrability of $Ck:> with respect to k from 0 to +OD we can see that we have to evaluate the S f„cp

3

C

x'P

)eikp

dP 1 2" J* expC—x

2) *expCikp) - 2 * [(p- rx)

2+d

2] dp + f expC—x

2)

* expC ikp) -OD * [ Cp-f" rx) 2+d

2] dpj expression. C 473 For the sake of calculating the first member in the right side of C47) let us consider the $ exp(ikz) [(z- rx)

2+d

2] *dz