199032. lajstromszámú szabadalom • Készülék tárolt adatok visszajátszására

HU 199032 B

Int Cl4 G 11 B 7/09

HF = AS + BS + CS + OS FE = (AS + CS)- (BS+DS) -- 0 TE = ES-FS= 0

FE =■ (AS + CS)- (BS+DS)< 0 TE = ES - FS = 0

C

L3

a

u

i

F

L3

L3

B

\

\J

0

A:

L1

1

A

If

D*

j-cu

1

JD

C

e

L2

L2

L2

FE =• (AS * CS) - (BS + DS) >0 TE = ES -FS= 0

FE = (AS + CS) - (BS+DS) = 0 TE = ES-FS < 0

FE - (AS+CS)-(BS + DS) * 0 r£ = ES-FS>0

Fig 1